The Python Oracle

When and why should I use a namedtuple instead of a dictionary?

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Chapters
00:00 Question
00:27 Accepted answer (Score 269)
01:49 Answer 2 (Score 47)
02:15 Thank you

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Full question
https://stackoverflow.com/questions/9872...

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Tags
#python

#avk47



ACCEPTED ANSWER

Score 280


In dicts, only the keys have to be hashable, not the values. namedtuples don't have keys, so hashability isn't an issue.

However, they have a more stringent restriction -- their key-equivalents, "field names", have to be strings.

Basically, if you were going to create a bunch of instances of a class like:

class Container:
    def __init__(self, name, date, foo, bar):
        self.name = name
        self.date = date
        self.foo = foo
        self.bar = bar

mycontainer = Container(name, date, foo, bar)

and not change the attributes after you set them in __init__, you could instead use

Container = namedtuple('Container', ['name', 'date', 'foo', 'bar'])

mycontainer = Container(name, date, foo, bar)

as a replacement.

Of course, you could create a bunch of dicts where you used the same keys in each one, but assuming you will have only valid Python identifiers as keys and don't need mutability,

mynamedtuple.fieldname

is prettier than

mydict['fieldname']

and

mynamedtuple = MyNamedTuple(firstvalue, secondvalue)

is prettier than

mydict = {'fieldname': firstvalue, 'secondfield': secondvalue}

Finally, namedtuples are ordered, unlike regular dicts, so you get the items in the order you defined the fields, unlike a dict.




ANSWER 2

Score 49


Tuples are immutable, whether named or not. namedtuple only makes the access more convenient, by using names instead of indices. You can only use valid identifiers for namedtuple, it doesn't perform any hashing — it generates a new type instead.