What is the quickest way to HTTP GET in Python?
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Track title: Puzzle Game Looping
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Chapters
00:00 Question
00:44 Accepted answer (Score 969)
01:05 Answer 2 (Score 488)
01:29 Answer 3 (Score 31)
01:47 Answer 4 (Score 20)
02:23 Thank you
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Full question
https://stackoverflow.com/questions/6453...
Accepted answer links:
[urllib.request]: https://docs.python.org/library/urllib.r...
[read]: https://docs.python.org/tutorial/inputou...
Answer 2 links:
[Requests]: https://docs.python-requests.org/en/late.../
Answer 4 links:
[httplib2]: https://github.com/httplib2/httplib2
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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
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Tags
#python #http #networking
#avk47
--
Music by Eric Matyas
https://www.soundimage.org
Track title: Puzzle Game Looping
--
Chapters
00:00 Question
00:44 Accepted answer (Score 969)
01:05 Answer 2 (Score 488)
01:29 Answer 3 (Score 31)
01:47 Answer 4 (Score 20)
02:23 Thank you
--
Full question
https://stackoverflow.com/questions/6453...
Accepted answer links:
[urllib.request]: https://docs.python.org/library/urllib.r...
[read]: https://docs.python.org/tutorial/inputou...
Answer 2 links:
[Requests]: https://docs.python-requests.org/en/late.../
Answer 4 links:
[httplib2]: https://github.com/httplib2/httplib2
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #http #networking
#avk47
ACCEPTED ANSWER
Score 1014
Python 3:
import urllib.request
contents = urllib.request.urlopen("http://example.com/foo/bar").read()
Python 2:
import urllib2
contents = urllib2.urlopen("http://example.com/foo/bar").read()
Documentation for urllib.request and read.
ANSWER 2
Score 518
Use the Requests library:
import requests
r = requests.get("http://example.com/foo/bar")
Then you can do stuff like this:
>>> print(r.status_code)
>>> print(r.headers)
>>> print(r.content) # bytes
>>> print(r.text) # r.content as str
Install Requests by running this command:
pip install requests
ANSWER 3
Score 31
If you want solution with httplib2 to be oneliner consider instantiating anonymous Http object
import httplib2
resp, content = httplib2.Http().request("http://example.com/foo/bar")
ANSWER 4
Score 20
Have a look at httplib2, which - next to a lot of very useful features - provides exactly what you want.
import httplib2
resp, content = httplib2.Http().request("http://example.com/foo/bar")
Where content would be the response body (as a string), and resp would contain the status and response headers.
It doesn't come included with a standard python install though (but it only requires standard python), but it's definitely worth checking out.