Multiple if statements in a lambda function

This video explains
Multiple if statements in a lambda function

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Music by Eric Matyas
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Track title: Life in a Drop

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Chapters
00:00 Question
00:45 Accepted answer (Score 27)
01:04 Answer 2 (Score 21)
01:26 Answer 3 (Score 1)
01:49 Thank you

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Full question
https://stackoverflow.com/questions/3343...

Accepted answer links:
[This]: http://ideone.com/wjeDnd
[Adam Smith's approach]: https://stackoverflow.com/a/33439510/390...

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python #lambda

#avk47

ACCEPTED ANSWER

You are missing an else before 'O'. This works:

y = lambda symbol: 'X' if symbol==True else 'O' if symbol==False else ' '

However, I think you should stick to Adam Smith's approach. I find that easier to read.

You can use an anonymous dict inside your anonymous function to test for this, using the default value of dict.get to symbolize your final "else"

y = lambda sym: {False: 'X', True: 'Y'}.get(sym, ' ')

This is one way where you can try multiple if else in lambda function

Example,

largest_num = lambda a,b,c : a if a>b and a>c else b if b>a and b>c else c if c>a and c>b else a

largest_num(3,8,14) will return 14