Print list without brackets in a single row

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Track title: Isolated

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Chapters
00:00 Question
00:45 Accepted answer (Score 347)
01:01 Answer 2 (Score 115)
01:18 Answer 3 (Score 61)
01:33 Answer 4 (Score 27)
02:04 Thank you

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Full question
https://stackoverflow.com/questions/1117...

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python #list

#avk47

ACCEPTED ANSWER

Score 367

print(', '.join(names))

This, like it sounds, just takes all the elements of the list and joins them with ', '.

ANSWER 2

Score 127

Here is a simple one.

names = ["Sam", "Peter", "James", "Julian", "Ann"]
print(*names, sep=", ")

the star unpacks the list and return every element in the list.

ANSWER 3

Score 61

General solution, works on arrays of non-strings:

>>> print str(names)[1:-1]
'Sam', 'Peter', 'James', 'Julian', 'Ann'

ANSWER 4

Score 29

If the input array is Integer type then you need to first convert array into string type array and then use join method for joining with , or space whatever you want. e.g:

>>> arr = [1, 2, 4, 3]
>>> print(", " . join(arr))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: sequence item 0: expected string, int found
>>> sarr = [str(a) for a in arr]
>>> print(", " . join(sarr))
1, 2, 4, 3
>>>

Direct using of join which will join the integer and string will throw error as show above.