Check if string matches pattern

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Track title: Puzzle Game 5 Looping

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Chapters
00:00 Question
00:34 Accepted answer (Score 655)
00:44 Answer 2 (Score 340)
01:06 Answer 3 (Score 55)
01:22 Answer 4 (Score 31)
01:35 Thank you

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Full question
https://stackoverflow.com/questions/1259...

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python #regex #stringmatching

#avk47

ACCEPTED ANSWER

Score 712

import re
pattern = re.compile("^([A-Z][0-9]+)+$")
pattern.match(string)

ANSWER 2

Score 391

One-liner: re.match(r"pattern", string) # No need to compile

import re
>>> if re.match(r"hello[0-9]+", 'hello1'):
...     print('Yes')
... 
Yes

You can evaluate it as bool if needed

>>> bool(re.match(r"hello[0-9]+", 'hello1'))
True

ANSWER 3

Score 58

Please try the following:

import re

name = ["A1B1", "djdd", "B2C4", "C2H2", "jdoi","1A4V"]

# Match names.
for element in name:
     m = re.match("(^[A-Z]\d[A-Z]\d)", element)
     if m:
        print(m.groups())

ANSWER 4

Score 32

import re
import sys

prog = re.compile('([A-Z]\d+)+')

while True:
  line = sys.stdin.readline()
  if not line: break

  if prog.match(line):
    print 'matched'
  else:
    print 'not matched'