How do I convert hex to decimal in Python?
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Track title: CC H Dvoks String Quartet No 12 Ame
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Chapters
00:00 Question
00:21 Accepted answer (Score 326)
00:44 Answer 2 (Score 54)
00:58 Answer 3 (Score 20)
01:33 Thank you
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Full question
https://stackoverflow.com/questions/9210...
Question links:
[Python]: http://en.wikipedia.org/wiki/Python_%28p...
Answer 1 links:
[Read the docs]: http://docs.python.org/library/functions...
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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
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Tags
#python #hex #decimal
#avk47
--
Track title: CC H Dvoks String Quartet No 12 Ame
--
Chapters
00:00 Question
00:21 Accepted answer (Score 326)
00:44 Answer 2 (Score 54)
00:58 Answer 3 (Score 20)
01:33 Thank you
--
Full question
https://stackoverflow.com/questions/9210...
Question links:
[Python]: http://en.wikipedia.org/wiki/Python_%28p...
Answer 1 links:
[Read the docs]: http://docs.python.org/library/functions...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #hex #decimal
#avk47
ACCEPTED ANSWER
Score 351
If by "hex data" you mean a string of the form
s = "6a48f82d8e828ce82b82"
you can use
i = int(s, 16)
to convert it to an integer and
str(i)
to convert it to a decimal string.
ANSWER 2
Score 59
ANSWER 3
Score 23
You could use a literal eval:
>>> ast.literal_eval('0xdeadbeef')
3735928559
Or just specify the base as argument to int:
>>> int('deadbeef', 16)
3735928559
A trick that is not well known, if you specify the base 0 to int, then Python will attempt to determine the base from the string prefix:
>>> int("0xff", 0)
255
>>> int("0o644", 0)
420
>>> int("0b100", 0)
4
>>> int("100", 0)
100