How do you round UP a number?

Become part of the top 3% of the developers by applying to Toptal https://topt.al/25cXVn

--

Music by Eric Matyas
https://www.soundimage.org
Track title: Hypnotic Puzzle2

--

Chapters
00:00 Question
00:31 Accepted answer (Score 1225)
00:54 Answer 2 (Score 294)
01:29 Answer 3 (Score 176)
02:06 Answer 4 (Score 175)
02:34 Thank you

--

Full question
https://stackoverflow.com/questions/2356...

Accepted answer links:
[math.ceil]: https://docs.python.org/3/library/math.h...

--

Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

--

Tags
#python #floatingpoint #integer #rounding

#avk47

ACCEPTED ANSWER

Score 1329

The math.ceil (ceiling) function returns the smallest integer higher or equal to x.

For Python 3:

import math
print(math.ceil(4.2))

For Python 2:

import math
print(int(math.ceil(4.2)))

ANSWER 2

Score 334

I know this answer is for a question from a while back, but if you don't want to import math and you just want to round up, this works for me.

>>> int(21 / 5)
4
>>> int(21 / 5) + (21 % 5 > 0)
5

The first part becomes 4 and the second part evaluates to "True" if there is a remainder, which in addition True = 1; False = 0. So if there is no remainder, then it stays the same integer, but if there is a remainder it adds 1.

ANSWER 3

Score 181

Interesting Python 2.x issue to keep in mind:

>>> import math
>>> math.ceil(4500/1000)
4.0
>>> math.ceil(4500/1000.0)
5.0

The problem is that dividing two ints in python produces another int and that's truncated before the ceiling call. You have to make one value a float (or cast) to get a correct result.

In javascript, the exact same code produces a different result:

console.log(Math.ceil(4500/1000));
5