Checking if List contains all items from another list

You can use sets

t1 = [ (1,2), (3,4), (5,6), (7,8), (9,10), (11,12) ]
t2 = [ (3,4), (11,12) ]
set(t2).issubset(t1)
# returns true

# or equivalent use '<=' so
set(t2) <= set(t1)
# returns true

For simplicity, you could do this:

print all(x in t1 for x in t2)

However, that's going to search through t1 for each element in t2. That probably doesn't matter when t1 is small as in this case, but to allow for larger collections I would do this:

s1 = set(t1)
print all(x in s1 for x in t2)

or this:

print set(t1).issuperset(t2)

This will generally be faster, since in is much faster for sets than for large lists. There's no major performance benefit in converting t2 to a set, regardless of size, so I wouldn't.

As always, it's better if you get your data in the "right" collection to begin with. So if the main purpose of t1 is to look things up in it, use a set in the first place rather than a list.

You can create sets from those lists and use issubset method:

>>> t1 = [ (1,2), (3,4), (5,6), (7,8), (9,10), (11,12) ]
>>> t2 = [ (3,4), (11,12) ]
>>> s1 = set(t1)
>>> s2 = set(t2)
>>> s2.issubset(s1)
True