How do I merge a list of dicts into a single dict?
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Chapters
00:00 Question
00:39 Accepted answer (Score 278)
00:58 Answer 2 (Score 169)
01:20 Answer 3 (Score 17)
01:46 Answer 4 (Score 13)
02:23 Thank you
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Full question
https://stackoverflow.com/questions/3494...
Question links:
[How to merge dicts, collecting values from matching keys?]: https://stackoverflow.com/questions/5946...
Accepted answer links:
[comprehension]: https://www.python.org/dev/peps/pep-0274/
Answer 2 links:
[ChainMap]: https://docs.python.org/3/library/collec...
[What is the purpose of collections.ChainMap?]: https://stackoverflow.com/questions/2339...
Answer 3 links:
[@dietbuddha]: https://stackoverflow.com/users/247357/d...
[PEP 448]: https://www.python.org/dev/peps/pep-0448/
[faster as well]: https://gist.github.com/treyhunner/f3529...
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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #list #dictionary
#avk47
--
Music by Eric Matyas
https://www.soundimage.org
Track title: Puzzle Game 5
--
Chapters
00:00 Question
00:39 Accepted answer (Score 278)
00:58 Answer 2 (Score 169)
01:20 Answer 3 (Score 17)
01:46 Answer 4 (Score 13)
02:23 Thank you
--
Full question
https://stackoverflow.com/questions/3494...
Question links:
[How to merge dicts, collecting values from matching keys?]: https://stackoverflow.com/questions/5946...
Accepted answer links:
[comprehension]: https://www.python.org/dev/peps/pep-0274/
Answer 2 links:
[ChainMap]: https://docs.python.org/3/library/collec...
[What is the purpose of collections.ChainMap?]: https://stackoverflow.com/questions/2339...
Answer 3 links:
[@dietbuddha]: https://stackoverflow.com/users/247357/d...
[PEP 448]: https://www.python.org/dev/peps/pep-0448/
[faster as well]: https://gist.github.com/treyhunner/f3529...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #list #dictionary
#avk47
ACCEPTED ANSWER
Score 319
This works for dictionaries of any length:
>>> result = {}
>>> for d in L:
... result.update(d)
...
>>> result
{'a':1,'c':1,'b':2,'d':2}
As a comprehension:
# Python >= 2.7
{k: v for d in L for k, v in d.items()}
# Python < 2.7
dict(pair for d in L for pair in d.items())
ANSWER 2
Score 187
In case of Python 3.3+, there is a ChainMap collection:
>>> from collections import ChainMap
>>> a = [{'a':1},{'b':2},{'c':1},{'d':2}]
>>> dict(ChainMap(*a))
{'b': 2, 'c': 1, 'a': 1, 'd': 2}
Also see:
ANSWER 3
Score 16
This is similar to @delnan but offers the option to modify the k/v (key/value) items and I believe is more readable:
new_dict = {k:v for list_item in list_of_dicts for (k,v) in list_item.items()}
for instance, replace k/v elems as follows:
new_dict = {str(k).replace(" ","_"):v for list_item in list_of_dicts for (k,v) in list_item.items()}
unpacks the k,v tuple from the dictionary .items() generator after pulling the dict object out of the list
ANSWER 4
Score 12
For flat dictionaries you can do this:
from functools import reduce
reduce(lambda a, b: dict(a, **b), list_of_dicts)