In Python, how do I check if a string has alphabets or numbers?

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Chapters
00:00 Question
00:24 Accepted answer (Score 17)
00:41 Answer 2 (Score 4)
01:19 Answer 3 (Score 2)
01:39 Answer 4 (Score 0)
01:52 Thank you

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Full question
https://stackoverflow.com/questions/6676...

Accepted answer links:
[thestring.isalnum()]: http://docs.python.org/2/library/stdtype...

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Tags
#python #regex

#avk47

ACCEPTED ANSWER

Score 18

Use thestring.isalnum() method.

>>> '123abc'.isalnum()
True
>>> '123'.isalnum()
True
>>> 'abc'.isalnum()
True
>>> '123#$%abc'.isalnum()
>>> a = '123abc' 
>>> (a.isalnum()) and (not a.isalpha()) and (not a.isnumeric())
True
>>>

ANSWER 2

Score 5

If you want to check if ALL characters are alphanumeric:

string.isalnum() (as @DrTyrsa pointed out), or
bool(re.match('[a-z0-9]+$', thestring, re.IGNORECASE))

If you want to check if at least one alphanumeric character is present:

import string
alnum = set(string.letters + string.digits)
len(set(thestring) & alnum) > 0

bool(re.search('[a-z0-9]', thestring, re.IGNORECASE))

ANSWER 3

Score 2

It might be a while, but if you want to figure out if the string at at least 1 alphabet or numeral, we could use

re.match('.\*[a-zA-Z0-9].\*', yourstring)