The Python Oracle

Count the number of occurrences of a character in a string

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Chapters
00:00 Question
00:22 Accepted answer (Score 1692)
00:45 Answer 2 (Score 184)
00:58 Answer 3 (Score 137)
01:15 Answer 4 (Score 63)
01:28 Thank you

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Full question
https://stackoverflow.com/questions/1155...

Accepted answer links:
[str.count(sub[, start[, end]])]: https://docs.python.org/3/library/stdtyp...

Answer 2 links:
[.count()]: https://docs.python.org/2/library/string...

Answer 3 links:
[collections.Counter]: https://docs.python.org/2/library/collec...

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Tags
#python #string #count

#avk47



ACCEPTED ANSWER

Score 1814


str.count(sub[, start[, end]])

Return the number of non-overlapping occurrences of substring sub in the range [start, end]. Optional arguments start and end are interpreted as in slice notation.

>>> sentence = 'Mary had a little lamb'
>>> sentence.count('a')
4



ANSWER 2

Score 197


You can use .count() :

>>> 'Mary had a little lamb'.count('a')
4



ANSWER 3

Score 61


Regular expressions maybe?

import re
my_string = "Mary had a little lamb"
len(re.findall("a", my_string))



ANSWER 4

Score 37


Python-3.x:

"aabc".count("a")

str.count(sub[, start[, end]])

Return the number of non-overlapping occurrences of substring sub in the range [start, end]. Optional arguments start and end are interpreted as in slice notation.