how to stop a for loop
This video explains
how to stop a for loop
--
Become part of the top 3% of the developers by applying to Toptal
https://topt.al/25cXVn
--
Music by Eric Matyas
https://www.soundimage.org
Track title: Mysterious Puzzle
--
Chapters
00:00 Question
00:44 Accepted answer (Score 98)
01:14 Answer 2 (Score 63)
02:52 Answer 3 (Score 4)
03:15 Answer 4 (Score 0)
03:30 Thank you
--
Full question
https://stackoverflow.com/questions/6346...
Answer 2 links:
[break]: http://docs.python.org/tutorial/controlf...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python
#avk47
how to stop a for loop
--
Become part of the top 3% of the developers by applying to Toptal
https://topt.al/25cXVn
--
Music by Eric Matyas
https://www.soundimage.org
Track title: Mysterious Puzzle
--
Chapters
00:00 Question
00:44 Accepted answer (Score 98)
01:14 Answer 2 (Score 63)
02:52 Answer 3 (Score 4)
03:15 Answer 4 (Score 0)
03:30 Thank you
--
Full question
https://stackoverflow.com/questions/6346...
Answer 2 links:
[break]: http://docs.python.org/tutorial/controlf...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python
#avk47
ACCEPTED ANSWER
Score 119
Use break and continue to do this. Breaking nested loops can be done in Python using the following:
for a in range(...):
for b in range(..):
if some condition:
# break the inner loop
break
else:
# will be called if the previous loop did not end with a `break`
continue
# but here we end up right after breaking the inner loop, so we can
# simply break the outer loop as well
break
Another way is to wrap everything in a function and use return to escape from the loop.
ANSWER 2
Score 5
Try to simply use break statement.
Also you can use the following code as an example:
a = [[0,1,0], [1,0,0], [1,1,1]]
b = [[0,0,0], [0,0,0], [0,0,0]]
def check_matr(matr, expVal):
for row in matr:
if len(set(row)) > 1 or set(row).pop() != expVal:
print 'Wrong'
break# or return
else:
print 'ok'
else:
print 'empty'
check_matr(a, 0)
check_matr(b, 0)
ANSWER 3
Score 0
Use the break statement: http://docs.python.org/reference/simple_stmts.html#break
ANSWER 4
Score 0
Others ways to do the same is:
el = L[0][0]
m=len(L)
print L == [[el]*m]*m
Or:
first_el = L[0][0]
print all(el == first_el for inner_list in L for el in inner_list)