The Python Oracle

How to sum all the values in a dictionary?

Become part of the top 3% of the developers by applying to Toptal https://topt.al/25cXVn

--

Music by Eric Matyas
https://www.soundimage.org
Track title: Ocean Floor

--

Chapters
00:00 Question
00:27 Accepted answer (Score 683)
00:38 Answer 2 (Score 71)
01:25 Answer 3 (Score 20)
01:41 Answer 4 (Score 7)
01:54 Thank you

--

Full question
https://stackoverflow.com/questions/4880...

Answer 1 links:
[six]: https://pypi.python.org/pypi/six/

--

Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

--

Tags
#python #dictionary #hash #sum

#avk47



ACCEPTED ANSWER

Score 736


As you'd expect:

sum(d.values())



ANSWER 2

Score 73


In Python 2 you can avoid making a temporary copy of all the values by using the itervalues() dictionary method, which returns an iterator of the dictionary's keys:

sum(d.itervalues())

In Python 3 you can just use d.values() because that method was changed to do that (and itervalues() was removed since it was no longer needed).

To make it easier to write version independent code which always iterates over the values of the dictionary's keys, a utility function can be helpful:

import sys

def itervalues(d):
    return iter(getattr(d, ('itervalues', 'values')[sys.version_info[0]>2])())

sum(itervalues(d))

This is essentially what Benjamin Peterson's six module does.




ANSWER 3

Score 21


Sure there is. Here is a way to sum the values of a dictionary.

>>> d = {'key1':1,'key2':14,'key3':47}
>>> sum(d.values())
62



ANSWER 4

Score 10


d = {'key1': 1,'key2': 14,'key3': 47}
sum1 = sum(d[item] for item in d)
print(sum1)

you can do it using the for loop