Function printing correct Output and None
--
Track title: CC M Beethoven - Piano Sonata No 3 in C 3
--
Chapters
00:00 Question
00:48 Accepted answer (Score 7)
01:40 Answer 2 (Score 5)
02:00 Answer 3 (Score 0)
02:31 Thank you
--
Full question
https://stackoverflow.com/questions/1246...
Accepted answer links:
[all]: http://docs.python.org/library/functions...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python
#avk47
ACCEPTED ANSWER
Score 7
Your program prints boolean, which is False, so you know where that comes from.
If a function doesn't return anything explicitly, it automatically returns None, and when you use
print uses_all('facebook', 'd')
you're asking it to print what uses_all returns, which is None. Hence:
False
None
BTW, I think your function could be more concisely written as
def uses_all(word, allused):
return all(e in word for e in allused)
Could make it more efficient, but that should be good enough for government work. The all function is really handy (see also any).
ANSWER 2
Score 5
Because uses_all() doesn't have a return statement. If you return a value from the function, it will be printed instead of None, unless of course you return None :)
ANSWER 3
Score 0
You print the result of the function, but the function doesn't return anything (--> None)
If you want the result to be False False, add return boolean in the function.
Alternatively, if a single False is enough, you could change print uses_all('facebook', 'd') to just uses_all('facebook', 'd')