How to convert an int to a hex string?

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Chapters
00:00 Question
00:39 Accepted answer (Score 278)
01:20 Answer 2 (Score 153)
01:36 Answer 3 (Score 86)
01:52 Answer 4 (Score 72)
02:34 Thank you

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Full question
https://stackoverflow.com/questions/2269...

Answer 2 links:
[hex()]: http://docs.python.org/library/functions...

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Tags
#python #string #hex #int

#avk47

ACCEPTED ANSWER

Score 289

You are looking for the chr function.

You seem to be mixing decimal representations of integers and hex representations of integers, so it's not entirely clear what you need. Based on the description you gave, I think one of these snippets shows what you want.

>>> chr(0x65) == '\x65'
True


>>> hex(65)
'0x41'
>>> chr(65) == '\x41'
True

Note that this is quite different from a string containing an integer as hex. If that is what you want, use the hex builtin.

ANSWER 2

Score 158

This will convert an integer to a 2 digit hex string with the 0x prefix:

strHex = "0x%0.2X" % integerVariable

ANSWER 3

Score 95

What about hex()?

hex(255)  # 0xff

If you really want to have \ in front you can do:

print '\\' + hex(255)[1:]

ANSWER 4

Score 51

Try:

"0x%x" % 255 # => 0xff

"0x%X" % 255 # => 0xFF

Python Documentation says: "keep this under Your pillow: http://docs.python.org/library/index.html"