django order_by query set, ascending and descending
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Chapters
00:00 Question
00:28 Accepted answer (Score 834)
00:45 Answer 2 (Score 86)
01:13 Answer 3 (Score 41)
01:39 Answer 4 (Score 28)
01:53 Thank you
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Full question
https://stackoverflow.com/questions/9834...
Accepted answer links:
[Django Documentation]: https://docs.djangoproject.com/en/dev/re...
Answer 2 links:
https://docs.djangoproject.com/en/dev/to...
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Tags
#python #django #sorting
#avk47
--
Music by Eric Matyas
https://www.soundimage.org
Track title: Lost Civilization
--
Chapters
00:00 Question
00:28 Accepted answer (Score 834)
00:45 Answer 2 (Score 86)
01:13 Answer 3 (Score 41)
01:39 Answer 4 (Score 28)
01:53 Thank you
--
Full question
https://stackoverflow.com/questions/9834...
Accepted answer links:
[Django Documentation]: https://docs.djangoproject.com/en/dev/re...
Answer 2 links:
https://docs.djangoproject.com/en/dev/to...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #django #sorting
#avk47
ACCEPTED ANSWER
Score 896
Reserved.objects.filter(client=client_id).order_by('-check_in')
Notice the - before check_in.
- before column name mean "descending order", while without - mean "ascending".
ANSWER 2
Score 89
Reserved.objects.filter(client=client_id).order_by('-check_in')
A hyphen "-" in front of "check_in" indicates descending order. Ascending order is implied.
We don't have to add an all() before filter(). That would still work, but you only need to add all() when you want all objects from the root QuerySet.
More on this here: https://docs.djangoproject.com/en/dev/topics/db/queries/#retrieving-specific-objects-with-filters
ANSWER 3
Score 31
You can also use the following instruction:
Reserved.objects.filter(client=client_id).order_by('check_in').reverse()
ANSWER 4
Score 20
for ascending order:
Reserved.objects.filter(client=client_id).order_by('check_in')
for descending order:
1. Reserved.objects.filter(client=client_id).order_by('-check_in')
or
2. Reserved.objects.filter(client=client_id).order_by('check_in')[::-1]