Remove trailing newline from the elements of a string list

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Track title: CC G Dvoks String Quartet No 12 Ame 2

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Chapters
00:00 Question
00:44 Accepted answer (Score 283)
01:16 Answer 2 (Score 130)
01:31 Answer 3 (Score 69)
01:49 Answer 4 (Score 8)
02:06 Thank you

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Full question
https://stackoverflow.com/questions/7984...

Answer 2 links:
[lists comprehensions]: http://docs.python.org/tutorial/datastru...
[map]: http://docs.python.org/library/functions...

Answer 3 links:
[PEP 202]: http://www.python.org/dev/peps/pep-0202/

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python #list #strip

#avk47

ACCEPTED ANSWER

Score 297

You can either use a list comprehension

my_list = ['this\n', 'is\n', 'a\n', 'list\n', 'of\n', 'words\n']
stripped = [s.strip() for s in my_list]

or alternatively use map():

stripped = list(map(str.strip, my_list))

In Python 2, map() directly returned a list, so you didn't need the call to list. In Python 3, the list comprehension is more concise and generally considered more idiomatic.

ANSWER 2

Score 130

list comprehension? [x.strip() for x in lst]

ANSWER 3

Score 70

You can use lists comprehensions:

strip_list = [item.strip() for item in lines]

Or the map function:

# with a lambda
strip_list = map(lambda it: it.strip(), lines)

# without a lambda
strip_list = map(str.strip, lines)

ANSWER 4

Score 8

This can be done using list comprehensions as defined in PEP 202

[w.strip() for w in  ['this\n', 'is\n', 'a\n', 'list\n', 'of\n', 'words\n']]