why OR returns True if the first element is True, but ANY still checks all element even if the first element is True

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00:00 Question
00:34 Accepted answer (Score 2)
01:11 Thank you

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Full question
https://stackoverflow.com/questions/5678...

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Tags
#python

#avk47

ACCEPTED ANSWER

Score 2

You're correct, any does short-circuit (only evaluates as much as needed) but as @alfasin said, you're creating the 1/0 error when you try and insert it into a list. To show the delayed evaluation, you'd have to do something like what I put in the comments or

def itr():
    yield 1
    yield 1/0

any(itr())  # --> True

class ErrorOnBool:
    def __bool__(self):
        raise RuntimeError()


any([1, ErrorOnBool()])   # --> True