How to get a random number between a float range?

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00:00 Question
00:22 Accepted answer (Score 935)
00:36 Answer 2 (Score 136)
00:55 Answer 3 (Score 87)
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Full question
https://stackoverflow.com/questions/6088...

Accepted answer links:
[random.uniform(a, b)]: http://docs.python.org/library/random.ht...

Answer 3 links:
[here]: http://docs.python.org/library/random.ht...

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Tags
#python #random #floatingpoint

#avk47

ACCEPTED ANSWER

>>> import random
>>> random.uniform(1.5, 1.9)
1.8733202628557872

if you want generate a random float with N digits to the right of point, you can make this :

round(random.uniform(1,2), N)

the second argument is the number of decimals.

random.uniform(a, b) appears to be what your looking for. From the docs:

Return a random floating point number N such that a <= N <= b for a <= b and b <= N <= a for b < a.

See here.

Most commonly, you'd use:

import random
random.uniform(a, b) # range [a, b) or [a, b] depending on floating-point rounding

Python provides other distributions if you need.

If you have numpy imported already, you can used its equivalent:

import numpy as np
np.random.uniform(a, b) # range [a, b)

Again, if you need another distribution, numpy provides the same distributions as python, as well as many additional ones.