How to find children of nodes using BeautifulSoup

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Full question
https://stackoverflow.com/questions/6287...

Answer 1 links:
https://www.crummy.com/software/Beautifu...

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Tags
#python #html #beautifulsoup

#avk47

ACCEPTED ANSWER

Try this

li = soup.find('li', {'class': 'test'})
children = li.findChildren("a" , recursive=False)
for child in children:
    print(child)

There's a super small section in the DOCs that shows how to find/find_all direct children.

In your case as you want link1 which is first direct child:

# for only first direct child
soup.find("li", { "class" : "test" }).find("a", recursive=False)

If you want all direct children:

# for all direct children
soup.find("li", { "class" : "test" }).findAll("a", recursive=False)

Perhaps you want to do

soup.find("li", { "class" : "test" }).find('a')

try this:

li = soup.find("li", { "class" : "test" })
children = li.find_all("a") # returns a list of all <a> children of li

other reminders:

The find method only gets the first occurring child element. The find_all method gets all descendant elements and are stored in a list.