Accessing dict_keys element by index in Python3
--
Track title: CC L Beethoven - Piano Sonata No 8 in C
--
Chapters
00:00 Question
00:36 Accepted answer (Score 270)
01:07 Answer 2 (Score 82)
01:53 Answer 3 (Score 12)
02:15 Answer 4 (Score 8)
02:33 Thank you
--
Full question
https://stackoverflow.com/questions/1855...
Accepted answer links:
[dictionary view object]: http://docs.python.org/3/library/stdtype...
Answer 2 links:
[Python 3.6]: https://www.google.nl/search?clien
Answer 3 links:
[detailed answer]: https://stackoverflow.com/questions/1622...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #dictionary #python3x #key
#avk47
ACCEPTED ANSWER
Score 297
Call list() on the dictionary instead:
keys = list(test)
In Python 3, the dict.keys() method returns a dictionary view object, which acts as a set. Iterating over the dictionary directly also yields keys, so turning a dictionary into a list results in a list of all the keys:
>>> test = {'foo': 'bar', 'hello': 'world'}
>>> list(test)
['foo', 'hello']
>>> list(test)[0]
'foo'
ANSWER 2
Score 89
Not a full answer but perhaps a useful hint. If it is really the first item you want*, then
next(iter(q))
is much faster than
list(q)[0]
for large dicts, since the whole thing doesn't have to be stored in memory.
For 10.000.000 items I found it to be almost 40.000 times faster.
*The first item in case of a dict being just a pseudo-random item before Python 3.6 (after that it's ordered in the standard implementation, although it's not advised to rely on it).
ANSWER 3
Score 17
Python 3
mydict = {'a': 'one', 'b': 'two', 'c': 'three'}
mykeys = [*mydict] #list of keys
myvals = [*mydict.values()] #list of values
print(mykeys)
print(myvals)
Output
['a', 'b', 'c']
['one', 'two', 'three']
Also see this detailed answer
ANSWER 4
Score 9
I wanted "key" & "value" pair of a first dictionary item. I used the following code.
key, val = next(iter(my_dict.items()))