How do I get user IP address in Django?
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Chapters
00:00 How Do I Get User Ip Address In Django?
00:36 Accepted Answer Score 584
01:17 Answer 2 Score 265
02:31 Answer 3 Score 95
03:05 Answer 4 Score 29
03:26 Answer 5 Score 19
04:14 Thank you
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Full question
https://stackoverflow.com/questions/4581...
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Tags
#python #django
#avk47
ACCEPTED ANSWER
Score 589
def get_client_ip(request):
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
if x_forwarded_for:
ip = x_forwarded_for.split(',')[0]
else:
ip = request.META.get('REMOTE_ADDR')
return ip
Make sure you have reverse proxy (if any) configured correctly (e.g. mod_rpaf installed for Apache).
Note: the above uses the first item in X-Forwarded-For, but you might want to use the last item (e.g., in the case of Heroku: Get client's real IP address on Heroku)
And then just pass the request as argument to it;
get_client_ip(request)
ANSWER 2
Score 268
You can use django-ipware which supports Python 2 & 3 and handles IPv4 & IPv6.
Install:
pip install django-ipware
Simple Usage:
# In a view or a middleware where the `request` object is available
from ipware import get_client_ip
ip, is_routable = get_client_ip(request)
if ip is None:
# Unable to get the client's IP address
else:
# We got the client's IP address
if is_routable:
# The client's IP address is publicly routable on the Internet
else:
# The client's IP address is private
# Order of precedence is (Public, Private, Loopback, None)
Advanced Usage:
Custom Header - Custom request header for ipware to look at:
i, r = get_client_ip(request, request_header_order=['X_FORWARDED_FOR']) i, r = get_client_ip(request, request_header_order=['X_FORWARDED_FOR', 'REMOTE_ADDR'])Proxy Count - Django server is behind a fixed number of proxies:
i, r = get_client_ip(request, proxy_count=1)Trusted Proxies - Django server is behind one or more known & trusted proxies:
i, r = get_client_ip(request, proxy_trusted_ips=('177.2.2.2')) # For multiple proxies, simply add them to the list i, r = get_client_ip(request, proxy_trusted_ips=('177.2.2.2', '177.3.3.3')) # For proxies with fixed sub-domain and dynamic IP addresses, use partial pattern i, r = get_client_ip(request, proxy_trusted_ips=('177.2.', '177.3.'))
Note: read this notice.
ANSWER 3
Score 95
Alexander's answer is great, but lacks the handling of proxies that sometimes return multiple IP's in the HTTP_X_FORWARDED_FOR header.
The real IP is usually at the end of the list, as explained here: http://en.wikipedia.org/wiki/X-Forwarded-For
The solution is a simple modification of Alexander's code:
def get_client_ip(request):
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
if x_forwarded_for:
ip = x_forwarded_for.split(',')[-1].strip()
else:
ip = request.META.get('REMOTE_ADDR')
return ip
ANSWER 4
Score 19
I would like to suggest an improvement to yanchenko's answer.
Instead of taking the first ip in the X_FORWARDED_FOR list, I take the first one which in not a known internal ip, as some routers don't respect the protocol, and you can see internal ips as the first value of the list.
PRIVATE_IPS_PREFIX = ('10.', '172.', '192.', )
def get_client_ip(request):
"""get the client ip from the request
"""
remote_address = request.META.get('REMOTE_ADDR')
# set the default value of the ip to be the REMOTE_ADDR if available
# else None
ip = remote_address
# try to get the first non-proxy ip (not a private ip) from the
# HTTP_X_FORWARDED_FOR
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
if x_forwarded_for:
proxies = x_forwarded_for.split(',')
# remove the private ips from the beginning
while (len(proxies) > 0 and
proxies[0].startswith(PRIVATE_IPS_PREFIX)):
proxies.pop(0)
# take the first ip which is not a private one (of a proxy)
if len(proxies) > 0:
ip = proxies[0]
return ip
I hope this helps fellow Googlers who have the same problem.