Downloading file with pysftp
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Track title: CC M Beethoven - Piano Sonata No 3 in C 3
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Chapters
00:00 Downloading File With Pysftp
00:43 Accepted Answer Score 39
01:44 Thank you
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Full question
https://stackoverflow.com/questions/4463...
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Tags
#python #sftp #pysftp
#avk47
Rise to the top 3% as a developer or hire one of them at Toptal: https://topt.al/25cXVn
--------------------------------------------------
Track title: CC M Beethoven - Piano Sonata No 3 in C 3
--
Chapters
00:00 Downloading File With Pysftp
00:43 Accepted Answer Score 39
01:44 Thank you
--
Full question
https://stackoverflow.com/questions/4463...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #sftp #pysftp
#avk47
ACCEPTED ANSWER
Score 39
Connection.get does not return anything. It downloads the remote file to a local path specified by the localpath argument. If you do not specify the argument, it downloads the file to the current working directory.
So if you want to download to a specific local directory instead, you want this:
sftp.get('directory/file.csv', '/local/path/file.csv')
If you really want to read the file to a variable (what I understand that you actually do not want), you need to use Connection.getfo, like:
flo = BytesIO()
sftp.getfo(remotepath, flo)
flo.seek(0)
Alternatively, use Paramiko library directly (without the pysftp wrapper).
See Read a file from server with SSH using Python.
Obligatory warning: Do not set cnopts.hostkeys = None, unless you do not care about security. For the correct solution see Verify host key with pysftp.