When and why should I use a namedtuple instead of a dictionary?
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Chapters
00:00 When And Why Should I Use A Namedtuple Instead Of A Dictionary?
00:22 Accepted Answer Score 279
01:41 Answer 2 Score 49
02:04 Thank you
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Full question
https://stackoverflow.com/questions/9872...
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https://meta.stackexchange.com/help/lice...
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Tags
#python
#avk47
ACCEPTED ANSWER
Score 280
In dicts, only the keys have to be hashable, not the values. namedtuples don't have keys, so hashability isn't an issue.
However, they have a more stringent restriction -- their key-equivalents, "field names", have to be strings.
Basically, if you were going to create a bunch of instances of a class like:
class Container:
def __init__(self, name, date, foo, bar):
self.name = name
self.date = date
self.foo = foo
self.bar = bar
mycontainer = Container(name, date, foo, bar)
and not change the attributes after you set them in __init__, you could instead use
Container = namedtuple('Container', ['name', 'date', 'foo', 'bar'])
mycontainer = Container(name, date, foo, bar)
as a replacement.
Of course, you could create a bunch of dicts where you used the same keys in each one, but assuming you will have only valid Python identifiers as keys and don't need mutability,
mynamedtuple.fieldname
is prettier than
mydict['fieldname']
and
mynamedtuple = MyNamedTuple(firstvalue, secondvalue)
is prettier than
mydict = {'fieldname': firstvalue, 'secondfield': secondvalue}
Finally, namedtuples are ordered, unlike regular dicts, so you get the items in the order you defined the fields, unlike a dict.
ANSWER 2
Score 49
Tuples are immutable, whether named or not. namedtuple only makes the access more convenient, by using names instead of indices. You can only use valid identifiers for namedtuple, it doesn't perform any hashing — it generates a new type instead.