Numpy: Why is numpy.array([2]).any() > 1 False?

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Chapters
00:00 Numpy: Why Is Numpy.Array([2]).Any() ≫ 1 False?
00:18 Accepted Answer Score 6
00:39 Answer 2 Score 3
00:50 Thank you

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Full question
https://stackoverflow.com/questions/1205...

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Tags
#python #numpy

#avk47

ACCEPTED ANSWER

Score 6

It does return True. But (True > 1) == False. While the first part is 2 > 1 which of course is True.

As others posted, you probably want:

(numpy.array([2])  > 1).any()

ANSWER 2

Score 3

Perhaps you are confusing it with this

>>> (numpy.array([2]) > 1).any()
True