Delete whole 3d array if contains any nan
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Music by Eric Matyas
https://www.soundimage.org
Track title: Puzzle Game 3 Looping
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Chapters
00:00 Delete Whole 3d Array If Contains Any Nan
00:39 Accepted Answer Score 1
01:01 Thank you
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Full question
https://stackoverflow.com/questions/7107...
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https://meta.stackexchange.com/help/lice...
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Tags
#python #numpyndarray
#avk47
    Rise to the top 3% as a developer or hire one of them at Toptal: https://topt.al/25cXVn
--------------------------------------------------
Music by Eric Matyas
https://www.soundimage.org
Track title: Puzzle Game 3 Looping
--
Chapters
00:00 Delete Whole 3d Array If Contains Any Nan
00:39 Accepted Answer Score 1
01:01 Thank you
--
Full question
https://stackoverflow.com/questions/7107...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #numpyndarray
#avk47
ACCEPTED ANSWER
Score 1
As already answered by Michael Szczesny, more Pythonic way would be:
filtered_images=a[~np.isnan(a).any(axis=(2,1))]
If that piece of code is hard to understand, then consider extracting each image with a for loop as follows:
filtered_images=list()
for value in a:
  if(np.isnan(value).any()!=True):
    filtered_images.append(value)
Both approaches should give you similar output!