Override Python's 'in' operator?
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Chapters
00:00 Override Python'S 'In' Operator?
00:17 Accepted Answer Score 359
00:24 Answer 2 Score 280
00:49 Answer 3 Score 3
01:08 Thank you
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Full question
https://stackoverflow.com/questions/2217...
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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
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Tags
#python #operatoroverloading #operators #inoperator
#avk47
Rise to the top 3% as a developer or hire one of them at Toptal: https://topt.al/25cXVn
--------------------------------------------------
Music by Eric Matyas
https://www.soundimage.org
Track title: Digital Sunset Looping
--
Chapters
00:00 Override Python'S 'In' Operator?
00:17 Accepted Answer Score 359
00:24 Answer 2 Score 280
00:49 Answer 3 Score 3
01:08 Thank you
--
Full question
https://stackoverflow.com/questions/2217...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #operatoroverloading #operators #inoperator
#avk47
ACCEPTED ANSWER
Score 359
ANSWER 2
Score 280
A more complete answer is:
class MyClass(object):
def __init__(self):
self.numbers = [1,2,3,4,54]
def __contains__(self, key):
return key in self.numbers
Here you would get True when asking if 54 was in m:
>>> m = MyClass()
>>> 54 in m
True
ANSWER 3
Score 3
Another way of having desired logic is to implement __iter__.
If you don't overload __contains__ python would use __iter__ (if it's overloaded) to check whether or not your data structure contains specified value.