How to read first N lines of a file?

Python 3:

with open(path_to_file) as input_file:
    head = [next(input_file) for _ in range(lines_number)]
print(head)

Python 2:

with open(path_to_file) as input_file:
    head = [next(input_file) for _ in xrange(lines_number)]
print head

Here's another way (both Python 2 & 3):

from itertools import islice

with open(path_to_file) as input_file:
    head = list(islice(input_file, lines_number))
print(head)

N = 10
with open("file.txt", "a") as file:  # the a opens it in append mode
    for i in range(N):
        line = next(file).strip()
        print(line)

If you want to read the first lines quickly and you don't care about performance you can use .readlines() which returns list object and then slice the list.

E.g. for the first 5 lines:

with open("pathofmyfileandfileandname") as myfile:
    firstNlines=myfile.readlines()[0:5] #put here the interval you want

Note: the whole file is read so is not the best from the performance point of view but it is easy to use, fast to write and easy to remember so if you want just perform some one-time calculation is very convenient

print firstNlines

One advantage compared to the other answers is the possibility to select easily the range of lines e.g. skipping the first 10 lines [10:30] or the lasts 10 [:-10] or taking only even lines [::2].

There is no specific method to read number of lines exposed by file object.

I guess the easiest way would be following:

lines =[]
with open(file_name) as f:
    lines.extend(f.readline() for i in xrange(N))