How to convert an int to a hex string?

--------------------------------------------------
Rise to the top 3% as a developer or hire one of them at Toptal: https://topt.al/25cXVn
--------------------------------------------------

Music by Eric Matyas
https://www.soundimage.org
Track title: Melt

--

Chapters
00:00 How To Convert An Int To A Hex String?
00:29 Accepted Answer Score 289
01:00 Answer 2 Score 51
01:15 Answer 3 Score 95
01:27 Answer 4 Score 158
01:38 Thank you

--

Full question
https://stackoverflow.com/questions/2269...

--

Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

--

Tags
#python #string #hex #int

#avk47

ACCEPTED ANSWER

Score 289

You are looking for the chr function.

You seem to be mixing decimal representations of integers and hex representations of integers, so it's not entirely clear what you need. Based on the description you gave, I think one of these snippets shows what you want.

>>> chr(0x65) == '\x65'
True


>>> hex(65)
'0x41'
>>> chr(65) == '\x41'
True

Note that this is quite different from a string containing an integer as hex. If that is what you want, use the hex builtin.

ANSWER 2

Score 158

This will convert an integer to a 2 digit hex string with the 0x prefix:

strHex = "0x%0.2X" % integerVariable

ANSWER 3

Score 95

What about hex()?

hex(255)  # 0xff

If you really want to have \ in front you can do:

print '\\' + hex(255)[1:]

ANSWER 4

Score 51

Try:

"0x%x" % 255 # => 0xff

"0x%X" % 255 # => 0xFF

Python Documentation says: "keep this under Your pillow: http://docs.python.org/library/index.html"