Serializing class instance to JSON
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Track title: Melt
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Chapters
00:00 Serializing Class Instance To Json
00:37 Accepted Answer Score 314
01:41 Answer 2 Score 25
02:10 Answer 3 Score 91
03:03 Answer 4 Score 32
03:09 Thank you
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Full question
https://stackoverflow.com/questions/1025...
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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
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Tags
#python #json #serialization #pickle
#avk47
ACCEPTED ANSWER
Score 314
The basic problem is that the JSON encoder json.dumps() only knows how to serialize a limited set of object types by default, all built-in types. List here: https://docs.python.org/3.3/library/json.html#encoders-and-decoders
One good solution would be to make your class inherit from JSONEncoder and then implement the JSONEncoder.default() function, and make that function emit the correct JSON for your class.
A simple solution would be to call json.dumps() on the .__dict__ member of that instance. That is a standard Python dict and if your class is simple it will be JSON serializable.
class Foo(object):
def __init__(self):
self.x = 1
self.y = 2
foo = Foo()
s = json.dumps(foo) # raises TypeError with "is not JSON serializable"
s = json.dumps(foo.__dict__) # s set to: {"x":1, "y":2}
The above approach is discussed in this blog posting:
Serializing arbitrary Python objects to JSON using _dict_
And, of course, Python offers a built-in function that accesses .__dict__ for you, called vars().
So the above example can also be done as:
s = json.dumps(vars(foo)) # s set to: {"x":1, "y":2}
ANSWER 2
Score 91
There's one way that works great for me that you can try out:
json.dumps() can take an optional parameter default where you can specify a custom serializer function for unknown types, which in my case looks like
def serialize(obj):
"""JSON serializer for objects not serializable by default json code"""
if isinstance(obj, date):
serial = obj.isoformat()
return serial
if isinstance(obj, time):
serial = obj.isoformat()
return serial
return obj.__dict__
First two ifs are for date and time serialization
and then there is a obj.__dict__ returned for any other object.
the final call looks like:
json.dumps(myObj, default=serialize)
It's especially good when you are serializing a collection and you don't want to call __dict__ explicitly for every object. Here it's done for you automatically.
So far worked so good for me, looking forward for your thoughts.
ANSWER 3
Score 32
Using jsonpickle
import jsonpickle
object = YourClass()
json_object = jsonpickle.encode(object)
ANSWER 4
Score 25
I just do:
data=json.dumps(myobject.__dict__)
This is not the full answer, and if you have some sort of complicated object class you certainly will not get everything. However I use this for some of my simple objects.
One that it works really well on is the "options" class that you get from the OptionParser module. Here it is along with the JSON request itself.
def executeJson(self, url, options):
data=json.dumps(options.__dict__)
if options.verbose:
print data
headers = {'Content-type': 'application/json', 'Accept': 'text/plain'}
return requests.post(url, data, headers=headers)