The Python Oracle

Remove the first character of a string

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Chapters
00:00 Remove The First Character Of A String
00:21 Accepted Answer Score 511
00:35 Answer 2 Score 39
00:56 Answer 3 Score 2
01:13 Answer 4 Score 52
01:46 Thank you

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Full question
https://stackoverflow.com/questions/4945...

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python #string

#avk47



ACCEPTED ANSWER

Score 511


python 2.x

s = ":dfa:sif:e"
print s[1:]

python 3.x

s = ":dfa:sif:e"
print(s[1:])

both prints

dfa:sif:e



ANSWER 2

Score 52


Your problem seems unclear. You say you want to remove "a character from a certain position" then go on to say you want to remove a particular character.

If you only need to remove the first character you would do:

s = ":dfa:sif:e"
fixed = s[1:]

If you want to remove a character at a particular position, you would do:

s = ":dfa:sif:e"
fixed = s[0:pos]+s[pos+1:]

If you need to remove a particular character, say ':', the first time it is encountered in a string then you would do:

s = ":dfa:sif:e"
fixed = ''.join(s.split(':', 1))



ANSWER 3

Score 39


Depending on the structure of the string, you can use lstrip:

str = str.lstrip(':')

But this would remove all colons at the beginning, i.e. if you have ::foo, the result would be foo. But this function is helpful if you also have strings that do not start with a colon and you don't want to remove the first character then.




ANSWER 4

Score 2


deleting a char:

def del_char(string, indexes):

    'deletes all the indexes from the string and returns the new one'

    return ''.join((char for idx, char in enumerate(string) if idx not in indexes))

it deletes all the chars that are in indexes; you can use it in your case with del_char(your_string, [0])