Check if any of the list of keys are present in a dictionary

You could use any and iterate over each key you want to check

if any(key in dict for key in ['asdf', 'qwer', 'zxcf']):
    # contains at least one of them

This will short-circuit and return True upon finding the first match, or will return False if it finds none.

You could also use &:

keys =  ['asdf', 'qwer', 'zxcf']
if d.keys() & keys:
    print(d)

You would need d.viewkeys() for python2.

Alternatively, make keys a set and see if the set is disjoint or not, which will be the fastest approach:

keys =  {'asdf', 'qwer', 'zxcf'}

if not keys.isdisjoint(d):
    print(d)

you could try using list comprehension in python:

if any([True for entry in your_list if entry in dict]):
    --dostuff--

EDIT: CoryKramer suggested to remove the '[]' in order to make this a generator, rather than evaluate the entire list before checking if any elements are "True":

if any(True for entry in your_list if entry in dict):
    --dostuff--