Count the number of occurrences of a character in a string
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Track title: Puzzle Game 2 Looping
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Chapters
00:00 Count The Number Of Occurrences Of A Character In A String
00:16 Answer 1 Score 61
00:26 Accepted Answer Score 1814
00:46 Answer 3 Score 197
00:55 Answer 4 Score 37
01:14 Thank you
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Full question
https://stackoverflow.com/questions/1155...
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Tags
#python #string #count
#avk47
Hire the world's top talent on demand or became one of them at Toptal: https://topt.al/25cXVn
--------------------------------------------------
Music by Eric Matyas
https://www.soundimage.org
Track title: Puzzle Game 2 Looping
--
Chapters
00:00 Count The Number Of Occurrences Of A Character In A String
00:16 Answer 1 Score 61
00:26 Accepted Answer Score 1814
00:46 Answer 3 Score 197
00:55 Answer 4 Score 37
01:14 Thank you
--
Full question
https://stackoverflow.com/questions/1155...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #string #count
#avk47
ACCEPTED ANSWER
Score 1814
str.count(sub[, start[, end]])Return the number of non-overlapping occurrences of substring
subin the range[start, end]. Optional argumentsstartandendare interpreted as in slice notation.
>>> sentence = 'Mary had a little lamb'
>>> sentence.count('a')
4
ANSWER 2
Score 197
You can use .count() :
>>> 'Mary had a little lamb'.count('a')
4
ANSWER 3
Score 61
Regular expressions maybe?
import re
my_string = "Mary had a little lamb"
len(re.findall("a", my_string))
ANSWER 4
Score 37
Python-3.x:
"aabc".count("a")
str.count(sub[, start[, end]])
Return the number of non-overlapping occurrences of substring sub in the range [start, end]. Optional arguments start and end are interpreted as in slice notation.