The Python Oracle

TypeError: 'dict_keys' object does not support indexing

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Chapters
00:00 Typeerror: 'Dict_keys' Object Does Not Support Indexing
00:27 Accepted Answer Score 264
00:55 Answer 2 Score 13
01:20 Answer 3 Score 0
01:36 Answer 4 Score 13
01:54 Thank you

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Full question
https://stackoverflow.com/questions/1732...

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python #python3x #dictionary

#avk47



ACCEPTED ANSWER

Score 264


Clearly you're passing in d.keys() to your shuffle function. Probably this was written with python2.x (when d.keys() returned a list). With python3.x, d.keys() returns a dict_keys object which behaves a lot more like a set than a list. As such, it can't be indexed.

The solution is to pass list(d.keys()) (or simply list(d)) to shuffle.




ANSWER 2

Score 13


You're passing the result of somedict.keys() to the function. In Python 3, dict.keys doesn't return a list, but a set-like object that represents a view of the dictionary's keys and (being set-like) doesn't support indexing.

To fix the problem, use list(somedict.keys()) to collect the keys, and work with that.




ANSWER 3

Score 13


Convert an iterable to a list may have a cost. Instead, to get the the first item, you can use:

next(iter(keys))

Or, if you want to iterate over all items, you can use:

items = iter(keys)
while True:
    try:
        item = next(items)
    except StopIteration as e:
        pass # finish



ANSWER 4

Score 0


Why you need to implement shuffle when it already exists? Stay on the shoulders of giants.

import random

d1 = {0:'zero', 1:'one', 2:'two', 3:'three', 4:'four',
     5:'five', 6:'six', 7:'seven', 8:'eight', 9:'nine'}

keys = list(d1)
random.shuffle(keys)

d2 = {}
for key in keys: d2[key] = d1[key]

print(d1)
print(d2)