Django - catch exception
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Chapters
00:00 Django - Catch Exception
00:40 Answer 1 Score 4
01:04 Accepted Answer Score 23
01:30 Answer 3 Score 1
01:57 Answer 4 Score 2
02:32 Thank you
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Full question
https://stackoverflow.com/questions/1089...
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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
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Tags
#python #django #exception
#avk47
    Hire the world's top talent on demand or became one of them at Toptal: https://topt.al/25cXVn
--------------------------------------------------
Music by Eric Matyas
https://www.soundimage.org
Track title: Unforgiving Himalayas Looping
--
Chapters
00:00 Django - Catch Exception
00:40 Answer 1 Score 4
01:04 Accepted Answer Score 23
01:30 Answer 3 Score 1
01:57 Answer 4 Score 2
02:32 Thank you
--
Full question
https://stackoverflow.com/questions/1089...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #django #exception
#avk47
ACCEPTED ANSWER
Score 23
You have three options here.
- Provide a 404 handler or 500 handler
 - Catch the exception elsewhere in your code and do appropriate redirection
 - Provide custom middleware with the 
process_exceptionimplemented 
Middleware Example:
class MyExceptionMiddleware(object):
    def process_exception(self, request, exception):
        if not isinstance(exception, SomeExceptionType):
            return None
        return HttpResponse('some message')
ANSWER 2
Score 4
You can raise a 404 error or simply redirect user onto your custom error page with error message
from django.http import Http404
#...
def your_view(request)
    #...
    try:
        #... do something
    except:
        raise Http404
        #or
        return redirect('your-custom-error-view-name', error='error messsage')
ANSWER 3
Score 2
If you want to get proper traceback and message as well. Then I will suggest using a custom middleware and add it to the settings.py middleware section at the end.
The following code will process the exception only in production. You may remove the DEBUG condition if you wish.
from django.http import HttpResponse
from django.conf import settings
import traceback
class ErrorHandlerMiddleware:
    def __init__(self, get_response):
        self.get_response = get_response
    def __call__(self, request):
        response = self.get_response(request)
        return response
    def process_exception(self, request, exception):
        if not settings.DEBUG:
            if exception:
                message = "{url}\n{error}\n{tb}".format(
                    url=request.build_absolute_uri(),
                    error=repr(exception),
                    tb=traceback.format_exc()
                )
                # Do whatever with the message now
            return HttpResponse("Error processing the request.", status=500)
ANSWER 4
Score 1
Another suggestion could be to use Django messaging framework to display flash messages, instead of an error page.
from django.contrib import messages
#...
def another_view(request):
    #...
    context = {'foo': 'bar'}
    try:
        #... some stuff here
    except SomeException as e:
        messages.add_message(request, messages.ERROR, e)
    return render(request, 'appname/another_view.html', context)
And then in the view as in Django documentation:
{% if messages %}
<ul class="messages">
    {% for message in messages %}
    <li{% if message.tags %} class="{{ message.tags }}"{% endif %}>{{ message }}</li>
    {% endfor %}
</ul>
{% endif %}