Changing an array of True and False answers to a hex value Python

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Chapters
00:00 Changing An Array Of True And False Answers To A Hex Value Python
00:51 Answer 1 Score 1
01:07 Accepted Answer Score 8
01:33 Answer 3 Score 1
01:46 Answer 4 Score 0
01:54 Thank you

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Full question
https://stackoverflow.com/questions/2558...

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python

#avk47

ACCEPTED ANSWER

Score 8

lists = [
    [True, True, True, False, False, True, False, False],
    [True, True, False, False, True, False, False, True],
    [True, False, False, True, False, False, True, True],
    [False, False, True, False, False, True, True, True],
    [False, True, False, False, True, True, True, False],
    [True, False, False, True, True, True, False, False],
    [False, False, True, True, True, False, False, True],
    [False, True, True, True, False, False, True, False],
]

for l in lists:
    zero_one = map(int, l)  # convert True to 1, False to 0  using `int`
    n = int(''.join(map(str, zero_one)), 2)  # numbers to strings, join them
                                             # convert to number (base 2)
    print('{:02x}'.format(n))  # format them as hex string using `str.format`

output:

ANSWER 2

Score 1

No need for a two steps process if you use reduce (assuming MSB is at left as usual):

b = [True, True, True, False, False, True, False, False]
val = reduce(lambda byte, bit: byte*2 + bit, b, 0)

print val
print hex(val)

Displaying:

228
0xe4

ANSWER 3

Score 1

If you want to combine a series of boolean values into one value (as a bitfield), you could do something like this:

x = [True, False, True, False, True, False ]
v = sum(a<<i for i,a in enumerate(x))
print hex(v)

ANSWER 4

Score 0

This should do it:

def bool_list_to_hex(list):
  n = 0
  for bool in list:
    n *= 2
    n += int(bool)
  return hex(n)