Reading a Delphi binary file in Python

Here is the full solutions thanks to hints from KillianDS and Ritsaert Hornstra

import struct
fh = open('my_file.dat', 'rb')
s = fh.read(40256)
vals = struct.unpack('iidddddd5025d', s)
dpoints, dloops, dtime, bT, sT, hI, LI, tm = vals[:8]
data = vals[8:]

I do not know how Delphi internally stores data, but if it is as simple byte-wise data (so not serialized and mangled), use struct. This way you can treat a string from a python file as binary data. Also, open files as binary file(open,'rb').

Please note that when you define a record in Delphi (like struct in C) the fields are layed out in order and in binary given the current alignment (eg Bytes are aligned on 1 byte boundaries, Words on 2 byte, Integers on 4 byte etc, but it may vary given the compiler settings.

When serialized to a file, you probably mean that this record is written in binary to the file and the next record is written after the first one starting at position sizeof( structure) etc etc. Delphi does not specify how thing should be serialized to/from file, So the information you give leaves us guessing.

If you want to make sure it is always the same without interference of any compiler setings, use packed record.

Real can have multiple meanings (it is an 48 bit float type for older Delphi versions and later on a 64 bit float (IEEE double)).

If you cannot access the Delphi code or compile it yourself, just ty to check the data with a HEX editor, you should see the boundaries of the records clearly since they start with Integers and only floats follow.