Is a Python dictionary an example of a hash table?

Yes, it is a hash mapping or hash table. You can read a description of python's dict implementation, as written by Tim Peters, here.

That's why you can't use something 'not hashable' as a dict key, like a list:

>>> a = {}
>>> b = ['some', 'list']
>>> hash(b)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: list objects are unhashable
>>> a[b] = 'some'
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: list objects are unhashable

You can read more about hash tables or check how it has been implemented in python and why it is implemented that way.

There must be more to a Python dictionary than a table lookup on hash(). By brute experimentation I found this hash collision:

>>> hash(1.1)
2040142438
>>> hash(4504.1)
2040142438

Yet it doesn't break the dictionary:

>>> d = { 1.1: 'a', 4504.1: 'b' }
>>> d[1.1]
'a'
>>> d[4504.1]
'b'

Sanity check:

>>> for k,v in d.items(): print(hash(k))
2040142438
2040142438

Possibly there's another lookup level beyond hash() that avoids collisions between dictionary keys. Or maybe dict() uses a different hash.

(By the way, this in Python 2.7.10. Same story in Python 3.4.3 and 3.5.0 with a collision at hash(1.1) == hash(214748749.8).)

(I haven't found any collisions in Python 3.9.6. Since the hashes are bigger -- hash(1.1) == 230584300921369601 -- I estimate it would take my desktop a thousand years to find one. So I'll get back to you on this.)

Yes. Internally it is implemented as open hashing based on a primitive polynomial over Z/2 (source).

To expand upon nosklo's explanation:

a = {}
b = ['some', 'list']
a[b] = 'some' # this won't work
a[tuple(b)] = 'some' # this will, same as a['some', 'list']