How to test if a class attribute is an instance method
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Chapters
00:00 How To Test If A Class Attribute Is An Instance Method
00:34 Answer 1 Score 7
00:40 Accepted Answer Score 22
00:47 Answer 3 Score 9
01:00 Answer 4 Score 5
01:16 Thank you
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Full question
https://stackoverflow.com/questions/1091...
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Content licensed under CC BY-SA
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Tags
#python #methods #attributes #instance
#avk47
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and get $2,000 discount on your first invoice
--------------------------------------------------
Music by Eric Matyas
https://www.soundimage.org
Track title: Dream Voyager Looping
--
Chapters
00:00 How To Test If A Class Attribute Is An Instance Method
00:34 Answer 1 Score 7
00:40 Accepted Answer Score 22
00:47 Answer 3 Score 9
01:00 Answer 4 Score 5
01:16 Thank you
--
Full question
https://stackoverflow.com/questions/1091...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #methods #attributes #instance
#avk47
ACCEPTED ANSWER
Score 22
def hasmethod(obj, name):
return hasattr(obj, name) and type(getattr(obj, name)) == types.MethodType
ANSWER 2
Score 9
You can use the inspect module:
class A(object):
def method_name(self):
pass
import inspect
print inspect.ismethod(getattr(A, 'method_name')) # prints True
a = A()
print inspect.ismethod(getattr(a, 'method_name')) # prints True
ANSWER 3
Score 7
import types
print isinstance(getattr(your_object, "your_attribute"), types.MethodType)
ANSWER 4
Score 5
This function checks if the attribute exists and then checks if the attribute is a method using the inspect module.
import inspect
def ismethod(obj, name):
if hasattr(obj, name):
if inspect.ismethod(getattr(obj, name)):
return True
return False
class Foo:
x = 0
def bar(self):
pass
foo = Foo()
print ismethod(foo, "spam")
print ismethod(foo, "x")
print ismethod(foo, "bar")