How do I get the filename without the extension from a path in Python?

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Chapters
00:00 How Do I Get The Filename Without The Extension From A Path In Python?
00:14 Accepted Answer Score 1868
00:38 Answer 2 Score 773
01:03 Answer 3 Score 279
01:10 Answer 4 Score 117
01:20 Thank you

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Full question
https://stackoverflow.com/questions/6782...

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python #string #path

#avk47

ACCEPTED ANSWER

Score 1868

Python 3.4+

Use pathlib.Path.stem

>>> from pathlib import Path
>>> Path("/path/to/file.txt").stem
'file'
>>> Path("/path/to/file.tar.gz").stem
'file.tar'

Python < 3.4

Use os.path.splitext in combination with os.path.basename:

>>> os.path.splitext(os.path.basename("/path/to/file.txt"))[0]
'file'
>>> os.path.splitext(os.path.basename("/path/to/file.tar.gz"))[0]
'file.tar'

ANSWER 2

Score 773

You can make your own with:

>>> import os
>>> base=os.path.basename('/root/dir/sub/file.ext')
>>> base
'file.ext'
>>> os.path.splitext(base)
('file', '.ext')
>>> os.path.splitext(base)[0]
'file'

Important note: If there is more than one . in the filename, only the last one is removed. For example:

/root/dir/sub/file.ext.zip -> file.ext

/root/dir/sub/file.ext.tar.gz -> file.ext.tar

See below for other answers that address that.

ANSWER 3

Score 279

>>> print(os.path.splitext(os.path.basename("/path/to/file/hemanth.txt"))[0])
hemanth

ANSWER 4

Score 117

In Python 3.4+ you can use the pathlib solution

from pathlib import Path

print(Path(your_path).resolve().stem)