Algorithm to get every possible subset of a list, in order of their product, without building and sorting the entire list (i.e Generators)
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Chapters
00:00 Algorithm To Get Every Possible Subset Of A List, In Order Of Their Product, Without Building And So
01:49 Accepted Answer Score 5
02:26 Thank you
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Full question
https://stackoverflow.com/questions/5111...
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Tags
#python #generator #dynamicprogramming #knapsackproblem #powerset
#avk47
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Track title: Isolated
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Chapters
00:00 Algorithm To Get Every Possible Subset Of A List, In Order Of Their Product, Without Building And So
01:49 Accepted Answer Score 5
02:26 Thank you
--
Full question
https://stackoverflow.com/questions/5111...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#python #generator #dynamicprogramming #knapsackproblem #powerset
#avk47
ACCEPTED ANSWER
Score 5
Nice question, it was quite tricky to solve. I can't think of a way to generate the combinations in order either, but I wield the mighty heapq (aka a priority queue) to keep the candidates sorted.
from heapq import heappush, heappop
import operator
def prob(ps):
""" returns the probability that *not* all ps are True """
return 1-reduce(operator.mul, ps)
def gen(ps):
# turn each to a tuple
items = ((x,) for x in sorted(ps, reverse=True))
# create a priority queue, sorted by probability
pq = [(prob(x),x) for x in items]
# because you wanted this
yield ()
# as long as there are valid combinations
while pq:
# get the best un-yielded combination, the pq makes sure of that
p, x = heappop(pq)
yield x
# generate all the combinations from this item
for other in ps:
# keeping the tuples sorted -> unique combinations
if other < x[-1]:
# create a new combination
new = x+(other,)
item = prob(new), new
# add it to the queue
heappush(pq,item)
a = [1, 0.1, 0.5]
print list(gen(a))