Convert base-2 binary number string to int
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Chapters
00:00 Convert Base-2 Binary Number String To Int
00:18 Accepted Answer Score 963
00:36 Answer 2 Score 39
01:07 Answer 3 Score 10
01:32 Answer 4 Score 55
01:42 Thank you
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Full question
https://stackoverflow.com/questions/8928...
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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
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Tags
#python
#avk47
ACCEPTED ANSWER
Score 963
You use the built-in int() function, and pass it the base of the input number, i.e. 2 for a binary number:
>>> int('11111111', 2)
255
ANSWER 2
Score 55
Just type 0b11111111 in python interactive interface:
>>> 0b11111111
255
ANSWER 3
Score 39
Another way to do this is by using the bitstring module:
>>> from bitstring import BitArray
>>> b = BitArray(bin='11111111')
>>> b.uint
255
Note that the unsigned integer (uint) is different from the signed integer (int):
>>> b.int
-1
Your question is really asking for the unsigned integer representation; this is an important distinction.
The bitstring module isn't a requirement, but it has lots of performant methods for turning input into and from bits into other forms, as well as manipulating them.
ANSWER 4
Score 10
Using int with base is the right way to go. I used to do this before I found int takes base also. It is basically a reduce applied on a list comprehension of the primitive way of converting binary to decimal ( e.g. 110 = 2**0 * 0 + 2 ** 1 * 1 + 2 ** 2 * 1)
add = lambda x,y : x + y
reduce(add, [int(x) * 2 ** y for x, y in zip(list(binstr), range(len(binstr) - 1, -1, -1))])