How can I randomly select an item from a list?
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Chapters
00:00 How Can I Randomly Select An Item From A List?
00:13 Accepted Answer Score 3486
00:44 Answer 2 Score 192
00:57 Answer 3 Score 48
01:24 Answer 4 Score 294
02:41 Thank you
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Full question
https://stackoverflow.com/questions/3064...
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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
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Tags
#python #list #random
#avk47
ACCEPTED ANSWER
Score 3486
Use random.choice():
import random
foo = ['a', 'b', 'c', 'd', 'e']
print(random.choice(foo))
For cryptographically secure random choices (e.g., for generating a passphrase from a wordlist), use secrets.choice():
import secrets
foo = ['battery', 'correct', 'horse', 'staple']
print(secrets.choice(foo))
secrets is new in Python 3.6. On older versions of Python you can use the random.SystemRandom class:
import random
secure_random = random.SystemRandom()
print(secure_random.choice(foo))
ANSWER 2
Score 294
If you want to randomly select more than one item from a list, or select an item from a set, I'd recommend using random.sample instead.
import random
group_of_items = {'a', 'b', 'c', 'd', 'e'} # a sequence or set will work here.
num_to_select = 2 # set the number to select here.
list_of_random_items = random.sample(group_of_items, num_to_select)
first_random_item = list_of_random_items[0]
second_random_item = list_of_random_items[1]
If you're only pulling a single item from a list though, choice is less clunky, as using sample would have the syntax random.sample(some_list, 1)[0] instead of random.choice(some_list).
Unfortunately though, choice only works for a single output from sequences (such as lists or tuples). Though random.choice(tuple(some_set)) may be an option for getting a single item from a set.
EDIT: Using Secrets
As many have pointed out, if you require more secure pseudorandom samples, you should use the secrets module:
import secrets # imports secure module.
secure_random = secrets.SystemRandom() # creates a secure random object.
group_of_items = {'a', 'b', 'c', 'd', 'e'} # a sequence or set will work here.
num_to_select = 2 # set the number to select here.
list_of_random_items = secure_random.sample(group_of_items, num_to_select)
first_random_item = list_of_random_items[0]
second_random_item = list_of_random_items[1]
EDIT: Pythonic One-Liner
If you want a more pythonic one-liner for selecting multiple items, you can use unpacking.
import random
first_random_item, second_random_item = random.sample({'a', 'b', 'c', 'd', 'e'}, 2)
ANSWER 3
Score 192
If you also need the index, use random.randrange
from random import randrange
random_index = randrange(len(foo))
print(foo[random_index])
ANSWER 4
Score 48
I propose a script for removing randomly picked up items off a list until it is empty:
Maintain a set and remove randomly picked up element (with choice) until list is empty.
s=set(range(1,6))
import random
while len(s)>0:
s.remove(random.choice(list(s)))
print(s)
Three runs give three different answers:
>>>
set([1, 3, 4, 5])
set([3, 4, 5])
set([3, 4])
set([4])
set([])
>>>
set([1, 2, 3, 5])
set([2, 3, 5])
set([2, 3])
set([2])
set([])
>>>
set([1, 2, 3, 5])
set([1, 2, 3])
set([1, 2])
set([1])
set([])