Is there a simple way to delete a list element by value?

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Chapters
00:00 Is There A Simple Way To Delete A List Element By Value?
00:30 Accepted Answer Score 1914
00:50 Answer 2 Score 90
01:06 Answer 3 Score 216
01:28 Answer 4 Score 24
01:41 Thank you

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Full question
https://stackoverflow.com/questions/2793...

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Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...

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Tags
#python #list

#avk47

ACCEPTED ANSWER

Score 1914

To remove the first occurrence of an element, use list.remove:

>>> xs = ['a', 'b', 'c', 'd']
>>> xs.remove('b')
>>> print(xs)
['a', 'c', 'd']

To remove all occurrences of an element, use a list comprehension:

>>> xs = ['a', 'b', 'c', 'd', 'b', 'b', 'b', 'b']
>>> xs = [x for x in xs if x != 'b']
>>> print(xs)
['a', 'c', 'd']

ANSWER 2

Score 216

Usually Python will throw an Exception if you tell it to do something it can't so you'll have to do either:

if c in a:
    a.remove(c)

or:

try:
    a.remove(c)
except ValueError:
    pass

An Exception isn't necessarily a bad thing as long as it's one you're expecting and handle properly.

ANSWER 3

Score 90

You can do

a=[1,2,3,4]
if 6 in a:
    a.remove(6)

but above need to search 6 in list a 2 times, so try except would be faster

try:
    a.remove(6)
except ValueError:
    pass

ANSWER 4

Score 24

Here's how to do it inplace (without list comprehension):

def remove_all(seq, value):
    pos = 0
    for item in seq:
        if item != value:
           seq[pos] = item
           pos += 1
    del seq[pos:]